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24x^2-62x+35=0
a = 24; b = -62; c = +35;
Δ = b2-4ac
Δ = -622-4·24·35
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-22}{2*24}=\frac{40}{48} =5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+22}{2*24}=\frac{84}{48} =1+3/4 $
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